SSC Selection Post 2020 PYQ — Question 56

The correct answer is option 2 i.e. ₹8,385.

 

A = P + SI = P(1 + rt)

$8756 = 6600 \left(1 + \frac{1}{100} \cdot \frac{14}{3} \right)$ 

$8756 = 6600 \left(1 + \frac{14}{300} \right) = 6600 \cdot \left(\frac{314}{300} \right)$

$\Rightarrow \frac{6600 \cdot 314}{300} = 8756$

SI = A - P = 8756 - 6600 = ₹2156

$SI = \frac{P \cdot R \cdot T}{100} \Rightarrow 2156 = \frac{6600 \cdot x \cdot \frac{14}{3}}{100}$

$2156 = \frac{6600 \cdot 14x}{300} \Rightarrow 2156 = \frac{92400x}{300} \Rightarrow 2156 = 308x \Rightarrow x = \frac{2156}{308} = 7$

$A_2 = P(1 + \frac{r}{100})^n = 6600(1.10)^2 = 6600 \cdot 1.21 = ₹7986$

$SI = \frac{P \cdot R \cdot T}{100} = \frac{7986 \cdot 10 \cdot 0.5}{100} = ₹399.3$

Final amount = ₹7986 + ₹399.3 = ₹8385.3 ≈ ₹8385