SSC CGL 2022 PYQ — Question 61

The correct answer is option 1 i.e. 4

Given:

tanA + cot A = 2

Concept Used:

(a + b)² = a² + b² + 2ab   ....(i)

tanA = 1/cotA   ...(ii)

Explanation:

Squarying both sides of the given equation, we get

(tanA + cot A)² = (2)² 

⇒ tan²A + cot²A + 2tanAcotA =4     ...{using equation(i)}

⇒ tan²A + cot²A + 2 = 4     ...(Using equation(ii)}

⇒ tan²A + cot²A = 2

Now, 2(tan²A + cot²A) = 2(2) = 4

Hence the value of 2( tan²A + cot²A) is 4.