If Sinθ × sec2θ = 2/3, 0° < θ < 90°, then the value of (tan2θ + cos2θ) is:
Show answer & explanation
Correct answer: C
Explanation
Correct Answer is option 3 i.e. 13/12
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Concept |
Understanding |
Application |
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tan30 = 1/√3 cos30 = √3/2 |
Given that: Sinθ × sec2θ = 2/3 tanθ × secθ = 2/3 tanθ = 2/3secθ If we put θ = 30, it will satisfy the above equation. |
(tan2θ + cos2θ) Putting θ = 30; ⇒ (tan230 + cos230) ⇒ 1/3 + 3/4 ⇒ 13/12 |