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SSC CHSL 2019 PYQ — Question 71

SSC CHSL - 3rd July 2019 - Shift 1 • Quantitative Aptitude • Q71

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If cot θ = √6, then the value of (cosec2θ + sec2θ)/(cosec2θ - sec2θ):

Show answer & explanation

Correct answer: B

Explanation

Correct Answer is option 2 i.e. 7/5

Understanding

Application

Given

Cot θ = √6

Hence, B = √6 and P = 1

H = √[(√6)2 + (12)] = √7

Hence,

Cosec θ = √7

Sec θ = √7/√6

 (cosec2θ + sec2θ)/(cosec2θ - sec2θ)

Putting the values:

⇒ (7 + 7/6)/(7 - 7/6)

⇒ (49/6)/(35/6)

⇒ 49/35 = 7/5