If sin (C+D) = √3/2 and sec (C-D) = , then what is the value of C and D?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 45° and 15°.
sin(C + D) = √3/2 = sin 60°
⇒ C + D = 60° .....(1)
sec(C - D) = 2/√3 = sec 30°
⇒ C - D = 30° .....(2)
From equations (1) and (2), we get
C = 45° and D = 15°
Therefore, the values of C and D are 45° and 15°.