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SSC CHSL 2024 PYQ — Question 68

SSC CHSL - 08 July 2024 - Shift 3 • Quantitative Aptitude • Q68

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If sinθ = 111211\over12 , then what will be the value of (tan θ + secθ)?

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Correct answer: A

Explanation

The correct answer is option 1 i.e. 23\sqrt{23}.

Given, sinθ = 111211\over12

P = 11 and H = 12

sinθ = P/H

tanθ = P/B

secθ = H/B

H2 = P2 + B2

According to the given question,

H2 = P2 + B2 

⇒ 144 = 121 + B2 

⇒ B = 23\sqrt{23}

Now, (tan θ + secθ) = 112311\over \sqrt{23} + 122312\over\sqrt{23}

⇒ 23\sqrt{23}