SSC Selection Post 2024 PYQ — Question 61

SSC Selection Post - Higher Secondary Level - 24 June 2024 - Shift 2 • Quantitative Aptitude • Q61

If for a non-zero x, 7x2 + 5x + 7 = 0, then the x3 + 1x3\frac{1}{x^3}is  _______________.

Show answer & explanation

Correct answer: D

Explanation

The correct answer is Option 4 i.e. 610343\frac{610}{343}.

7x2 + 5x + 7 = 0....(1)

Divide the equation by x

7x + 5 + 7x7\over x = 0

⇒ 7x + 7x7\over x = -5......(2)

⇒ x + 1x1\over x = −57-5\over7

x3 + 1x31\over x^3 = (x + 1x1\over x)3 - 3(x + 1x1\over x)

⇒ x3 + 1x31\over x^3 = (−57-5\over7)3 - 3(−57-5\over7)

⇒ −125343-125\over343 + 15715\over7 = −125+735343-125+735\over343 = 610343\frac{610}{343}