SSC CHSL 2020 PYQ — Question 62

SSC CHSL - 13th October 2020 - Shift 2 • Quantitative Aptitude • Q62

If CosA, SinA, CotA are in geometric progression, then the value of Tan6A – Tan2A is:

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e 1

Understanding Application
We will use the properties of G.P. to simplify the problem.

CosA, SinA & CotA are in G.P. so,

⇒ Sin2A = CosA × CotA

⇒ Sin3A = Cos2A

Divide both sides by Cos3A (We want to convert to Tan3A)

⇒ Tan3A = SecA

⇒ Tan6A = Sec2A

We will now use trigonometric basic identities to transform the equation in a known format.

⇒ Tan6A – Tan2A

⇒ Sec2A - Tan2A

We know that Sec2A - Tan2A = 1

⇒ 1