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SSC CHSL 2020 PYQ — Question 63

SSC CHSL - 13th October 2020 - Shift 2 • Quantitative Aptitude • Q63

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If A = (0.1)3 + (0.2)3 + (0.3)3 + 3(0.005 + 0.016 + 0.027) + 0.036/(0.1)2 + (0.2)2 + (0.3)2 + 0.04 + 0.06 + 0.12, then the value of 60A is:

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Correct answer: A

Explanation

The correct answer is option 1 i.e 36

Here A = (0.1)3 + (0.2)3 + (0.3)3 + 3(0.005 + 0.016 + 0.027) + 0.036 /(0.1)2 + (0.2)2 + (0.3)2 + 0.04 + 0.06 + 0.12

⇒ A = 0.001 + 0.008 + 0.027 + 3(0.048) + 0.036 / 0.01 + 0.04 + 0.09 + 0.04 + 0.06 + 0.12

⇒ A = 0.001 + 0.008 + 0.027 + 0.144 + 0.036 / 0.01 + 0.04 + 0.09 + 0.04 + 0.06 + 0.12

⇒ A = 0.216 / 0.36 = 0.6

⇒ 60A = 60(0.6) = 36