SSC CHSL 2019 PYQ — Question 69

SSC CHSL - 9th July 2019 - Shift 1 • Quantitative Aptitude • Q69

If Cos x = -√3/2 and π < x < 3π/2, then the value of 2Cot2x + 3Cosec2x is:

Show answer & explanation

Correct answer: D

Explanation

The Correct Answer is option 4 i.e. 18.

Given that

Cos x = -√3/2 and π < x < 3π/2

Hence,

x = 7π/6 = 210°

Cos 210° = Cos(180 + 30) = -Cos 30°= -√3/2

Cot 210° = Cot(180 + 30) = Cot 30°= √3

Cosec 210° = Cosec(180 + 30) = -Cosec 30° = -2

Now,

2Cot2x + 3Cosec2x

Put x = 60°

⇒ 2 × 3 + 3 × (-2)2

⇒ 6 + 12 = 18