SSC CGL 2024 PYQ — Question 64

The correct answer is Option 2  ​​​​i.e. 2 .

⇒ $a^2 + b^2 + c^2 = 2(a + c - 1)$

⇒ $a^2 + b^2 + c^2 = 2a + 2c - 2$

⇒ $a^2 + b^2 + c^2 - 2a - 2c + 2 = 0$

Substituting ( a = 1 ) and ( c = 1 )  into the equation:

⇒ $1^2 + b^2 + 1^2 = 2(1 + 1 - 1)$

⇒ 1 + b² + 1 = 2

⇒ b² + 2 = 2

⇒ b² = 0

⇒ $a^3 + b^3 + c^3 = 1^3 + 0^3 + 1^3 = 1 + 0 + 1 = 2$