SSC CHSL 2021 PYQ — Question 62

SSC CHSL - 19 April 2021 - Shift 3 • Quantitative Aptitude • Q62

If a2 + 49b2 + c2 + 18 = 2 (28b - c - a) then the value of (a + 7b - c) is:

Show answer & explanation

Correct answer: D

Explanation

The correct answer is Option 4 i.e. 4.

Given that 

a2 + 49b2 + c2 + 18 = 2 (28b - c - a)

a2 + 1 + 2a + 49b2 + 16 - 56b + c2 + 1 + 2c = 0

(a + 1)2 + (7b - 4)2 + (c +1)2 = 0

a = -1

b = 4/7

c = -1

Put these values in (a + 7b - c)

= -1 + 7 * (4/7) + 1 = 4