From a point P that is at a distance of 15 cm from center O of a circle of radius 9 cm, in the same plane, a pair of tangents PQ and PR is drawn to circle. The area of quadrilateral PQOR is:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. 108 cm2.
Given that
OP =15 cm
OQ = OR = radius of circle = 9 cm
QR = √(225 - 81) = 12 cm
The area of quadrilateral PQOR = 2 * The area of triangle OPQ
= 2 * ½ * 9 * 12 = 108 cm2