If a natural number when divided by 4, 5, 7, and 6 leaves a remainder of 3 in each case, then what is the smallest possible three-digit natural number?
Show answer & explanation
Correct answer: B
Explanation
The Correct answer is Option 2 i.e. 423.
LCM - smallest number which will be completely divisibly by the given numbers
For finding the number which will leave the remainder 3, will be (LCM + 3)
LCM of (4, 5, 7, and, 6) = 7 × 5 × 3 × 2 × 2 = 420
The number that will leave the remainder is 3 = 420 + 3 = 423