A vendor sells 40 percent of the oranges he had and throws away 10 percent of the remainder. The next day he sells 50 percent of the remaining and throws away the rest. What percent of his oranges does the vendor throw?
Show answer & explanation
Correct answer: C
Explanation
The Correct answer is Option 3 i.e. 33 percent.
Let the number of oranges be 100x.
Number of oranges sold = 40% of 100x = 40x
Remaining oranges = 100x - 40x = 60x
The vendor throw away 10% of the remaining oranges = 10% of 60x = 6x
Remaining oranges = 60x - 6x = 54x
On the next day, he sold 50% of the oranges = 50% of 54x = 27x
Remaining oranges were thrown away = 54x - 27x = 27x
The total number of oranges that were thrown away = 27x + 6x = 33x
Hence, required percentage = (33x/100x) × 100 = 33%