If a man’s age is four times the sum of the ages of his three children, and after 6 years his age will be twice the sum of the ages of his three children, then what is the man’s present age?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 60 years.
Let the present age of the man be M.
The present sum of the ages of his three children = S
According to the question,
⇒ M = 4S
Now, after 6 years
⇒ M + 6 = 2(S + 18)
Using equations I and II, we get
⇒ 4S + 6 = 2S + 36
⇒ 2S = 36 - 6
⇒ S = 30/2
⇒ S = 15
Hence, the present age of the man = M = 4S
⇒ 4 × 15 = 60 years