SSC CHSL 2024 PYQ — Question 6

SSC CHSL Tier II 2024 Actual Exam - 18/11/2024 • Quantitative Aptitude • Q6

If 88 is replaced by 93 and 41 is replaced by 47 in the following observations, 46, 48, 63, 76, 88, 41, 35, 55, 90, 56, 92, then what would be the difference between the new median and the previous median?

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e. 0.

We know,

when the observations (n) are odd in number,

Median = (n + 1)/2 term

Now Original observations: 46, 48, 63, 76, 88, 41, 35, 55, 90, 56, 92

Arranging the original data in ascending order:

35, 41, 46, 48, 55, 56, 63, 76, 88, 90, 92

Number of observation = 11

Median = (11 + 1)/2 = 6th value = 56

Now, the new median also has 11 observations so the median value will also be 6th.

Replacing 88 with 93 and 41 with 47, we get

35, 46, 47, 48, 55, 56, 63, 76, 90, 92, 93

Median = 6th value = 56

Hence, the required difference = 56 - 56 = 0