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SSC Selection Post 2019 PYQ — Question 57

SSC Selection Post - Matriculation Level 2019 - 15 Oct 2019 • Quantitative Aptitude • Q57

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If a + b + c = 8 and ab + bc + ca = 11, then what is the value of a3 + b​​​​​​​3 + c3-3abc?

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Correct answer: A

Explanation

The correct answer is Option 1 i.e. 248.

a3+b3+c3−3abc=(a+b+c)3−3(a+b+c)(ab+bc+ca)a^3 + b^3 + c^3 - 3abc = (a + b + c)^3 - 3(a + b + c)(ab + bc + ca)

=83−3×8×11=512−264=248= 8^3 - 3 \times8 \times 11 = 512 - 264 = 248