If a + b + c = 6, a2 + b2 + c2 = 14 and ab + bc + ca = 11, then what is the value of a3 + b3 + c3 - 3abc?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 18.
Given:
a + b + c = 6, a2 + b2 + c2 = 14 and ab + bc + ca = 11
Formula used:
a3 + b3 + c3 - 3abc = (a + b + c)(a2 + b2 + c2 - (ab + bc + ca)) ---- (1)
Calculations:
Using equation (1), we get
a3 + b3 + c3 - 3abc = (6)(14 - 11)
⇒ 6 × 3 = 18