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SSC Selection Post 2022 PYQ — Question 65

SSC Selection Post - Matriculation Level 2022 - 2 Feb 2022 - Shift 2 • Quantitative Aptitude • Q65

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If a : b = 7 : 4, then find (2a + 7b) : (7a + 2a).

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Correct answer: A

Explanation

The correct answer is option 1 i.e. 3 : 1.

a = 7x, b = 4x

2a+7b7a+2a=2(7x)+7(4x)7(7x)+2(7x)\frac{2a + 7b}{7a + 2a} = \frac{2(7x) + 7(4x)}{7(7x) + 2(7x)}

simplify the numerator : 2(7x) + 7(4x) = 14x + 28x = 42x

simplify the denominator : 7(7x) + 2(7x) = 49x + 14x = 63x

⇒42x63x=4263=2:3\Rightarrow \frac{42x}{63x} = \frac{42}{63} = 2 : 3