If 8(x + y)3 - (x - y)3 = (x + 3y) (Ax2 + Bxy + Cy2), then value of (A - B - C) is:
Show answer & explanation
Correct answer: A
Explanation
Correct Answer is option 1 i.e. -2
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Application |
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Given: 8(x + y)3 - (x - y)3 = (x + 3y) (Ax2 + Bxy + Cy2) 8(x + y)3 - (x - y)3 can be written as: ⇒ [2(x + y)]3 – [x – y]3 Now, expanding it: ⇒ [2(x + y) – (x – y)] [(2(x + y))2 + 2(x + y) × (x - y) + (x - y)2] ⇒ [2x + 2y – x + y] [4x2 + 4y2 + 8xy + 2x2 – 2y2 + x2 + y2 – 2xy] ⇒ [x + 3y] [7x2 + 3y2 + 6xy] Now, (x + 3y) (Ax2 + Bxy + Cy2) = [x + 3y] [7x2 + 3y2 + 6xy] Comparing the coefficients: A = 7, B = 6 and C = 3 Hence, (A – B – C) = 7 – 6 – 3 = -2 |