If 5 sin2 θ =3 (1 + cos θ), 0° < θ <90° , then the value of cosecθ + cotθ is
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Correct answer: A
Explanation
The correct answer is Option 1 i.e.
Given that
5 sin2 θ =3 (1 + cos θ)
5 (1 - cos2 θ) = 3 (1 + cos θ)
5 cos2 θ + 3 cos θ - 2 =0
cos θ = 2/5
sin θ = √21/5
Now, cosecθ + cotθ = 5/√21 + 2/√21 = 7/√21 =