SSC CHSL 2021 PYQ — Question 63

SSC CHSL - 13 April 2021 - Shift 1 • Quantitative Aptitude • Q63

If 2x2−6x=1{{2x^2-6x=1}} then x2+14x2=?x^2+{{1} \over 4x^2}=?

Show answer & explanation

Correct answer: C

Explanation

The correct answer is Option 3 i.e. 10.

Given that 

2x2−6x=1{{2x^2-6x=1}}

x - (1/2x) = 3

x2+14x2=x^2+{{1} \over 4x^2}=  9 + 2 * ½ = 10