SSC CGL 2019 PYQ — Question 50

SSC CGL - 4th June 2019 - Shift 1 • Quantitative Aptitude • Q50

If 4 – 2sin2θ – 5cos θ = 0, 0° < θ < 90°, then the value of sin θ + tan θ is:

Show answer & explanation

Correct answer: B

Explanation

 The correct answer is option 2 i.e. 3√3/2

Concept

Understanding

Sin2θ = 1 – cos2θ

 

Cos θ is always less than or equal to 1

Given that:

4 – 2sin2θ – 5 cosθ = 0

Using Sin2θ = 1 – cos2θ:

⇒ 4 – 2(1 - cos2θ) – 5cos θ = 0

⇒ 2cos2θ - 5cos θ + 2 = 0

⇒ 2cos2θ - 4cos θ - cos θ + 2 = 0

⇒ 2cosθ (cosθ – 2) –1(cosθ – 2)

⇒ (2cosθ – 1) (cosθ – 2)

⇒ cos θ = 2, 1/2 (cos θ cannot be 2)

so, cos θ = 1/2

⇒ θ = 60°

Hence,

sin θ + tan θ = √3/2 + √3

⇒ 3√3/2