If 321y72 is a multiple of 6, where y is a digit, what is the least value of y?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e 0.
Divisibility of 6: A number is divisible by 6 if it is divisible by both 2 and 3.
Divisibility of 2: Any number that is evebn, i.e., it ends with 0, 2, 4, 6, 8 is divisible by 2.
Divisibility of 3: If the sum of the digits of the number is divisible by 3, the number is divisible by 3.
According to the given question,
Number = 321y72
It is an even number and is divisible by 2.
The sum of digits of the number = 3 + 2 + 1 + y + 7 + 2 = 15 + y
The least value of y = 0
Hence the required answer is 0.