SSC CGL 2024 PYQ — Question 62

SSC CGL - 26 Sep 2024 - Shift 2 • Quantitative Aptitude • Q62

If 2a−b=32a-b=3 and 8a3−b3=9998a^3-b^3=999 , then the value of 4a2−b24a^2-b^2.

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Correct answer: A

Explanation

The correct answer is option 1 i.e. 63.

x³ - y³ = (x - y)(x² + xy + y²)

Here, 2a - b = 3

⇒ (2a - b)2 = 32 = 9

⇒ 4a2 - 4ab + b2 = 9   .....(1)

Also, 8a3 - b3 = 999

⇒ (2a - b)(4a2 + 2ab + b2) = 999

⇒ 3(4a2 + 2ab + b2) = 999

⇒ (4a2 + 2ab + b2) = 999/3 = 333   .....(2)

Subtracting equation (1) from (2),

6ab = 324

⇒ ab = 54

Putting ab = 54 into the equation (1),

4a2 - 4(54) + b2 = 9

⇒ 4a2 - 216 + b2 = 9

⇒ 4a2 + b2 = 225

Now, (2a + b)2 = 4a2 + 4ab + b2 = 225 + 4(54) = 225 + 216 = 441

⇒ 2a + b = √441 = 21

So, 4a2 - b2 = (2a - b)(2a + b) = 3 × 21 = 63

Therefore, the value of 4a2 - b2 is 63.