Height of a tower is 120 metres. The angle of elevation of the top of tower from a point B is 75°. Point B is on the ground level. What is the distance (in metres) of point B from the base of tower?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e. 120(2 − √3)
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Application |
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From the figure: Tan75 = 120/Base Base = 120/Tan75 = 120/[(√3 + 1)/(√3 – 1)] = 120 × [(4 – 2√3)/(3 – 1)] = 120(2 – √3) |
