Given that ΔABC is congruent to ΔDEF. If AC = 11 m, ED = 6 m, EF = 15 m, ∠FDE = 85°, and ∠ABC = 55°, then the perimeters of triangles ABC and ∠EFD are, respectively:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 32 m, 40°.

∆ABC ≅ ∆DEF
AC = DF = 11 m; ED = AB = 6 m; EF = BC = 15 m
∠FDE = ∠CAB = 85° and ∠ABC = ∠DEF = 55°
Perimeter of ∆ABC = 6 + 15 + 11 = 32 m
∠DEF + ∠FDE + ∠EFD = 180°
⇒ 55° + 85° + ∠EFD = 180°
⇒ ∠EFD = 180° - 140° = 40°