From a point P which is at a distance of 10 cm from the centre O of a circle of radius 6 cm, a pair of tangents PQ and PR to the circle at point Q and R respectively, are drawn. Then the area of the quadrilateral PQOR is equal to
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Correct answer: D
Explanation
The correct answer is Option 4 i.e. 48 sq. cm
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According to question OP = 10 cm and OR = OQ = 6 cm Hence ΔPRO and ΔPQO are two right-angle triangles So PR and PQ = 102 - 62 = 100 - 36 = 64 So PQ = PR = 8 cm |
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Area of quadrilateral PQOR = area of ΔPRO and ΔPQO = 2( area ΔPRO) = 2 × (1/2 × 6 × 8) = 48 sq. cm |