Find the value of (14×34÷114of25)÷(34÷123of45)−(12−12×14)(\frac{1}{4}\times \frac{3}{4} \div 1\frac{1}{4} of \frac{2}{5})\div(\frac{3}{4}\div1\frac{2}{3}of\frac{4}{5})-(\frac{1}{2}-\frac{1}{2}\times\frac{1}{4})(41×43÷141of52)÷(43÷132of54)−(21−21×41). A724\frac{7}{24}247 B23\frac{2}{3}32 C512\frac{5}{12}125 D1112\frac{11}{12}1211 Show answer & explanationCorrect answer: AExplanationThe correct answer is option 1 i.e. 724\frac{7}{24}247 By using BODMAS rule, (14×34÷114of25)÷(34÷123of45)−(12−12×14)(\frac{1}{4}\times \frac{3}{4} \div 1\frac{1}{4} of \frac{2}{5})\div(\frac{3}{4}\div1\frac{2}{3}of\frac{4}{5})-(\frac{1}{2}-\frac{1}{2}\times\frac{1}{4})(41×43÷141of52)÷(43÷132of54)−(21−21×41) = (14×34÷12)÷(34÷43)−(12−18)(\frac{1}{4}\times \frac{3}{4} \div \frac{1}{2})\div(\frac{3}{4}\div\frac{4}{3})-(\frac{1}{2}-\frac{1}{8})(41×43÷21)÷(43÷34)−(21−81) = (14×34×21)÷(34×34)−38(\frac{1}{4}\times \frac{3}{4} \times \frac{2}{1})\div(\frac{3}{4}\times\frac{3}{4})-\frac{3}{8}(41×43×12)÷(43×43)−83 = 38×(43×43)−38\frac{3}{8}\times(\frac{4}{3}\times\frac{4}{3})-\frac{3}{8}83×(34×34)−83 = 23−38=724\frac{2}{3}-\frac{3}{8} = \frac{7}{24}32−83=247