SSC GD 2021 PYQ — Question 62

SSC GD Constable (English) - 18th November 2021 Shift 1 • Quantitative Aptitude • Q62

Find the value of (14×34÷114of25)÷(34÷123of45)−(12−12×14)(\frac{1}{4}\times \frac{3}{4} \div 1\frac{1}{4} of \frac{2}{5})\div(\frac{3}{4}\div1\frac{2}{3}of\frac{4}{5})-(\frac{1}{2}-\frac{1}{2}\times\frac{1}{4}).

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Correct answer: A

Explanation

The correct answer is option 1 i.e. 724\frac{7}{24}

By using BODMAS rule,

(14×34÷114of25)÷(34÷123of45)−(12−12×14)(\frac{1}{4}\times \frac{3}{4} \div 1\frac{1}{4} of \frac{2}{5})\div(\frac{3}{4}\div1\frac{2}{3}of\frac{4}{5})-(\frac{1}{2}-\frac{1}{2}\times\frac{1}{4})

= (14×34÷12)÷(34÷43)−(12−18)(\frac{1}{4}\times \frac{3}{4} \div \frac{1}{2})\div(\frac{3}{4}\div\frac{4}{3})-(\frac{1}{2}-\frac{1}{8})

= (14×34×21)÷(34×34)−38(\frac{1}{4}\times \frac{3}{4} \times \frac{2}{1})\div(\frac{3}{4}\times\frac{3}{4})-\frac{3}{8}

= 38×(43×43)−38\frac{3}{8}\times(\frac{4}{3}\times\frac{4}{3})-\frac{3}{8}

= 23−38=724\frac{2}{3}-\frac{3}{8} = \frac{7}{24}