Find the sum of the digits of the smallest 6-digit number divisible by 18, 24, and 25.
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e. 9.
Given that,
The smallest six-digit number is 100,000
LCM (18, 24, 25)
⇒ 18 = 2 × 3 × 3
⇒ 24 = 2 × 2 × 2 × 3
⇒ 25 = 5 × 5
LCM(18, 24, and 30) = 2 × 2 × 2 × 3 × 3 × 5 × 5 = 1800
Now,
The smallest six-digit number, 100000, is divided by 1800
⇒ 100000 ÷ 1800 = 5.55
This implies that the six-digit number divisible by 18, 24, and 25 can be given as
⇒ 6 × 1800 = 10800
Hence, the sum of the digits of this 6-digit smallest number is 9