Find the remainder when the smallest 6-digit number divisible by 12, 15, and 25 is divided by 9.
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e 3.
Let the smallest 6-digit number = 100000
The LCM of (12, 15, 25) = 300
The smallest 6-digit number which is divisible by (12, 15, 25) = 100200
When this number 100200 is divided by 9 then, the remainder will be = 3
Hence, the required remainder is 3