A, B, and C together can complete a piece of work in 40/3 days. All three started working at it together and after 5 days A left. Then B and C together completed the remaining work in 17 days. Find the number of days (approximately) in which A alone can complete the total work.
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e 26 DAYS
Given that
A, B, and C together can complete a piece of work in 40/3 days.
After 5 days A left.
According to the question
(A + B + C) × 40/3 = (A + B + C) × 5 + (B + C) × 17
(A + B + C) × (40/3 - 5 ) = (B + C) × 17
(A + B + C) × 25/3 = (B + C) × 17
A × 25/3 = (B + C) × (17 - 25/3)
A × 25/3 = (B + C) × 26/3
A : (B + C) = 26: 25
Now,
Total work = (A + B + C) × 40/3 = (26 + 25) × 40/3 = 680 units
A alone can complete the total work = 680/26 = 26.15 ≈ 26 days (approx)