SSC CGL 2020 PYQ — Question 67

SSC CGL - 7th March 2020 Shift 3 • Quantitative Aptitude • Q67

Find the product of (a + b + 2c)(a2 + b2 + 4c2 - ab - 2bc - 2ca).

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e a3 + b3 + 8c3 - 6abc

⇒ (a + b + 2c)(a2 + b2 + 4c2 - ab - 2bc - 2ca)

As we know that, (a + b + c)(a2 + b2 + c2 - ab - bc - ac) = (a3 + b3 + c3 - 3abc)

⇒ (a + b + 2c)(a2 + b2 + (2c)2 - ab - 2c(b) - 2c(a))

⇒ (a3 + b3 + 8c2 - 6abc)