Find the least number which when divided by 12, 18, 24 and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 364
According to the question,
Least number must be = LCM (12, 18, 24, 30)k + 4.
=360k + 4
At k = 1
360 + 4 = 364.
364 is also a multiple of 7.
No condition violates.