SSC CHSL 2021 PYQ — Question 51

SSC CHSL - 19 April 2021 - Shift 2 • Quantitative Aptitude • Q51

Chords AB and CD of a circle are produced to meet at the point P, outside the circle, and AD is the diameter of the circle. If ∠\angleDAP = 36° and ∠\angleAPC = 30°, then what will be the measure of ∠\angleCBD?

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 24°

Given:

AD is diameter.

 ∠\angleDAP = 36° and ∠\angleAPC = 30°

Concept Used:

Exterior angle of a triangle = Sum of the two opposite interior angles of the triangle.

Angles in the same segment are equal.

Explanation:

According to the given question,

Now, in triangle ADP, 

∠\angleADC = ∠\angleDAP + ∠\angleAPD   (∠\angleADC is exterior angle)

⇒ ∠\angleADC = 36° + 30° 

⇒ ∠\angleADC = 66°

Now, ∠\angleADC = ∠\angleABC = 66°   (Angles in the same segment)

Since AD is diameter, ∠\angleABD = 90°

So, ∠\angleCBD = ∠\angleABD - ∠\angleABC = 90° - 66° = 24°

Hence the requied answer is 24°.