C1 and C2 are two concentric circles such that the radius of C2 is less than the radius of C1. If AB is the chord of C1 of length 12 cm, touching C2 at P, find the length of AP.
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e. 6 cm.
Let O be the center of both circles
We draw a perpendicular OP on AB
OP cuts AB into two equal parts
Such that,
⇒ AP = PB
⇒ AB = 12 cm then,
length of AP = = = 6 cm