At a workplace, one man alone can complete a work in 32 days. If the entire staff, i.e., 6 women and 4 men, can complete the work in 6 days, how many days will one woman alone take to complete the entire work?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 144.
Let work = 32 (LCM of 32 and 6)
1 man’s rate = 32/32 = 1
Staff’s combined rate = 6W + 4M = 32/6 = 16/3
⇒ 6W + 4 = 16/3
⇒ 6W = 4/3
⇒ W = 2/9
Time for 1 woman = 32/(2/9) = 144 days