Alok starts walking from P with speed of 6 km/h towards Q.Raman starts at same time from P towards Q with speed of 9 km/h Raman reaches Q,turns back and starts walking towards P.He meets Alok at R.If PQ is 15 km,then what is PR?
Show answer & explanation
Correct answer: B
Explanation
Correct Answer is option 2 i.e. 12 km
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Understanding |
Application |
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Speed of Alok = 6 km/hr Speed of Raman = 9 km/hr PQ = 15 km |
Time in which Raman will reach Q = 15/9 = 5/3 hours Distance covered by Alok in 5/3 hours = 5/3 × 6 = 10 km So, Remaining distance = 15 – 10 = 5 km Since, Raman returned back after reaching Q: Time in which Alok and Raman will meet at R = 5/(9 + 6) = 5/15 = 1/3 hours So, Distance covered by Alok in 1/3 hours = 1/3 × 6 = 2 km Hence, PR = 10 + 2 = 12 km |