Alloy A contains metals x and y only in the ratio 5 : 2, while alloy B contains them in the ratio 3 ; 4. Alloy C is prepared by mixing alloys A and B in the ratio 4 : 5. The percentage of x in alloy C is:
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Correct answer: D
Explanation
The correct answer is option 4 i.e. 55
The ratio of the Component of x and y in A = 5 : 2 = 7 units.
The ratio of the Component of x and y in B = 3 : 4 = 7 units.
A and B is mixed in the ratio of 4 : 5
In 4 times of A, component of x and y in A becomes = 20 : 8
in 5 times of B, component of x and y in B becomes = 15 : 20
In C, the ratio of the component of x and y = 20 + 15 : 8 + 20 = 35 : 28
Ratio of component of x and y in C = 5 : 4
% of x in C = 5/9 × 100 = 55.55% = 55%.