SSC MTS 2024 PYQ — Question 2

SSC MTS - 16/10/2024 - (9:00 AM - 11:00 AM) • Quantitative Aptitude • Q2

Ajit walks around a circular field at the speed of two rounds per hour, while Mohit runs around it at the speed of 10 rounds per hour. They start in the same direction from the same point at 6.30 a.m. Find the time at which they cross each other.

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 06 : 37 : 30.

Ajit and Mohit move in same direction, they will first meet when there is difference of one round between the two.

Relative speed of Ajit amd Mohit = 10 - 2 = 8 rounds per hour 

Time taken to complete one round = (1/8) × 60 = 7 minutes 30 seconds

They will meet each other at 6.30 a.m. + 7 min 30 sec = 6 : 37 : 30 a.m.