SSC MTS 2024 PYQ — Question 3

SSC MTS - 16/10/2024 - (9:00 AM - 11:00 AM) • Quantitative Aptitude • Q3

A man on a tour of 400 km, travels the first 120 km at 80 km/h and the next 150 km at 75 km/h. If he must spend less than 5 hours in the tour, what is the minimum speed at which he has to travel for the remaining distance?

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 86.66 km/h.

Time taken by man to cover 120 km = 120/80 = 1.5 h

Time taken by man to cover 150 km = 150/75 = 2 h 

Total time of travel = 3.5 h

Remaining time that can be permitted for travel = 5 - 3.5 = 1.5 h

Remaining distance = 400 - 120 - 150 = 130 km

Minimum speed = 130/1.5 = 86.66 km/h