ABCD is a cyclic quadrilateral. Sides AB and DC when produced meet at E, and sides BC and AD, when produced, meet at F. If ∠BFA = 60° and ∠AED = 30°, then the measure of ∠ABC is?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. 75
| Application |
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Given that ABCD is a cyclic quadrilateral. Sides AB and DC, when produced, meet at E, and sides BC and AD, when produced, meet at F. If ∠BFA = 60o and ∠AED = 30o as shown in the figure below
∠ADC = 180° - ∠ABC (Sum of opposite angles of a cyclic quadrilateral is 180°)………………..(1) ∠BCD = 180° - ∠BAD (Sum of opposite angles of a cyclic quadrilateral is 180°)………………(2) Also, ∠ADC + ∠FDC = 180° (linear pair) So, ∠FDC = 180° - ∠ADC From (1) ∠FDC = ∠ABC………………(3) Now, ∠BCD+ ∠FCD =180° (linear pair) So, ∠FCD = 180° - ∠BCD From (2) ∠FCD = ∠BAD………………(4) In triangle FDC ∠FDC + ∠FCD + ∠DFC = 180° ∠ABC + ∠BAD + 60° = 180° ∠ABC + ∠BAD = 120°……………………….(5) In triangle AED ∠EAD + ∠ADE + ∠AED = 180° 180° - ∠BAD + ∠ABC = 180° - 30° ∠BAD - ∠ABC = 30° Subtract (6) from (5) 2∠ABC = 150° ∠ABC = 75° |
