AB is a common tangent to both the circles in the given figure. Find the distance (correct to two decimal places) between the
centres of the two circles.

Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 23.58 Units

Given:-
AB is a common tangent to C(c, 5cm) and C(d, x cm)
Thus, ang(CAE) = ang(DBE) = 90 degree
AC = 5 units
AE = 8 units
BE = 12 units
To find:-
Length of the line joining the centers of both circles (CD)
Solution:-
We know CD = CE + DE
We know in △AEC
AE2 + AC2 = CE2 (By Pythagorus Theorem)
25 + 64 = CE2
CE2 = 89
CE ~ 9.43 units
In △BDE
we have to find 'x'.
Thus we will use similarity rules to find the value of 'x'.
Thus, In △AEC and △BDE
ang(CAE) = ang(DBE) (both are 90º, as AB is tangent to both the circles)
ang(AC) = ang(DEB) (Vertically Opposite Angles are equal)
Thus, due to A.A similarity rule
△AEC ~ △BED
Thus, x = 7.5 cm
Now in △BDE
ED2 = BE2 + BD2
ED2 = 122 + 7.52
ED2 = 200.25
ED ~ 14.15
Thus, CD = CE + ED
CD = 9.43 + 14.15
CD = 23.58