AB is a chord of a circle having a radius 1.7 cm. If the distance of this chord AB from the center of the circle is 0.8 cm, then what is the length (in cm) of the chord AB?
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Correct answer: C
Explanation
The correct answer is option 3 i.e. 3
The radius of the circle = 1.7 cm
Distance of this chord AB from the center of the circle = 0.8 cm
Pythagoras theorem;
H2 = B2 + P2
Where, H = hypotenuse, B = base and P = perpendicular
From the above figure;
⇒ OB2 = OD2 + BD2
⇒ 1.72 = 0.82 + BD2
⇒ BD2 = 2.25
⇒ BD = 1.5 cm
We know, AB = BD × 2 = 1.5 × 2 = 3 cm