SSC MTS 2022 PYQ — Question 59

SSC MTS - 19 July 2022 - Shift 3 • Quantitative Aptitude • Q59

A train can cover a certain distance in 3 hrs. If the track management is improved, an increase in the speed of the train by 10 km/h is possible, which can reduce the above journey time by 30 minutes. Find the initial speed of the train.

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e  50 km/h

Concept Used :

Distance = Speed × Time

Now, let the initial speed of the train be X km/hr.

So, the distance covered by train in 3 hrs = 3X km    ...(i)

Now the increased speed of the train is (X + 10) km/hr.

The decrease in the time of journey = 30 minutes 

So the new time = 2 hours 30 minutes = 5/2 hrs.

So the distance covered by new speed = (X + 10) × 5/2  ...(ii)

Now from equation (i) and (ii),

⇒ 3X = (X + 10) × 5/2

⇒ 3X - 5X/2 = 25

⇒ X/2 = 25

⇒ X = 50.

Hence the initial speed of the train is 50 km/hr.