A thief is spotted by a policeman from a distance of 195 metres. When the policeman starts the chase, the thief also starts running. If the speed of the thief is 22 km/h and that of the policeman is 27 km/h, then how far would the thief have run (in m) before he is overtaken?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 858.
Relative speed = 27 - 22 = 5 km/h = 5 × m/s
Time required for the policeman =
Distance covered by the thief = Time × Speed = × 22 × = 39 × 22 = 858 m
Therefore, the thief would have run 858 meters before being overtaken.