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SSC MTS 2022 PYQ — Question 66

SSC MTS - 19 July 2022 - Shift 3 • Quantitative Aptitude • Q66

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A sum of ₹2,400 is invested for 4 years at R% p.a, simple interest and the simple interest received is ₹1,152. Find the amount received after 3 years when the same sum is invested at (R + 8) % p.a, simple interest.

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Correct answer: D

Explanation

The correct answer is option 4 i.e ₹3,840

Concept Used :

SI=P×R×T100SI = {P \times R \times T \over 100}

Amount = Principle + Interest

Given :

P = ₹2,400, T = 4 years, SI = ₹1,152

Now, using the formula,

⇒ 1,152 = (2,400 × 4 × R)/100

⇒ R = 1,152/96

⇒ R = 12 %

Now, New rate = (R + 8)% = 12 + 8 = 20 %

New time = 3 years

Now, SI = (2,400 × 20 × 3)/100

SI = 1,440

So, Amount = 2,400 + 1,440 = 3,840

Hence the required amount is ₹3,840.