SSC CGL 2025 PYQ — Question 57

SSC CGL - 15 Sep 2025 - Shift 3 • Quantitative Aptitude • Q57

A student walks from his home to school at a speed of 4 km/h and reaches 15 minutes late. If he increases his speed to 6 km/h, he reaches 5 minutes early. What is the distance (in km) from his home to school?

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 4 km.

Let distance = d km

Time at 4 km/h = d4d\over4

Time at 6 km/h = d6d\over6

Late by 15 min and early by 5 min

difference = 20 min = 131\over3 hr

⇒ d4d\over4 − d6d\over6 = 131\over3

⇒ 3d−2d123d − 2d \over 12 = 131\over3

⇒ d12d\over12 = 131\over3

⇒ d = 4 km