A solution contains acid and water in the ratio of 4:5. If 20% of the solution is replaced by water, then what will be the ratio of acid and water in the new solution?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 16:29
Let the total solution be 90 units,
The amount of acid = 90 × 4/9 = 40 units
The amount of water = 90 × 5/9 = 50 units
20% of total solution is taken out = 90 × 20/100 = 18 units
Acid and water will be taken out in 4 : 5
⇒ The remaining amount of acid = 40 - 18 × 4/9 = 32
⇒ The remaining amount of water = 50 - 18 × 5/9 = 40
The amount taken out is replaced with water;
Hence, new quantity of water = 40 + 18 = 58